Resolve \(\frac{3}{x^2 + x - 2}\) into partial fractions
A. \(\frac{1}{x - 1} - \frac{1}{x + 2}\)
B. \(\frac{1}{x + 1} + \frac{1}{x - 2}\)
C. \(\frac{1}{x + 1} - \frac{1}{x - 2}\)
D. \(\frac{1}{x - 2} + \frac{1}{x + 2}\)
Correct Answer: A
Explanation
\(\frac{3}{x^2 + x - 2}\) = \(\frac{3}{(x - 1)(x + 2)}\)
\(\frac{A}{x - 1}\) + \(\frac{B}{x + 2}\)
A(x + 2) + B(x - 1) = 3
when x = 1, 3A = 3 \(\to\) a = 1
when x = -2, -3B = 3 \(\to\) B = -1
= \(\frac{1}{x - 1} -Â \frac{1}{x + 2}\)
