Fifty boxes each of 50 bolts were inspected for the number which were defective. The following was the result \(\begin{array}{c|c} \text{No. defective per box} & 4 & 5 & 6 & 7 & 8 & 9 \\ \hline \text{No. of boxes} & 2 & 7 & 17 & 10 & 8 & 6\end{array}\) Find the percentage of boxes containing at least 5 defective bolts each
A. 96 B. 94 C. 92 D. 90
Correct Answer: A
Explanation
% of boxes containing at least 5 defective bolts each = \(\frac{7 + 17 + 10 + 8 + 6}{50}\) = \(\frac{48}{50}\) x \(\frac{100}{1}\) = 96%
