Fifty boxes each of 50 bolts were inspected for the number which were defective. The following was the result \(\begin{array}{c|c} \text{No. defective per box} & 4 & 5 & 6 & 7 & 8 & 9 \\ \hline \text{No. of boxes} & 2 & 7 & 17 & 10 & 8 & 6\end{array}\) The mean and the median of the distribution are respectively
A. 6.7, 6 B. 7.6, 5 C. 5.7, 87 D. 34, 6
Correct Answer: A
Explanation
No of defective(x)
No of boxes (f)
\(fx\)
4
2
8
5
7
35
6
17
102
7
10
70
8
8
64
9
6
54
\(\sum\)
50
333
\(Mean = \frac{\sum fx}{\sum f}\) = \(\frac{333}{50} = 6.66 \approxeq 6.7\) The median is the average of the 25th and 26th position = 6. Â
