A cylinder of base radius 5 cm is open at one end. If its height is 10 cm what is the ratio of its base area to its curved surface area?
Explanation
To find the ratio of the base area to the curved surface area of the cylinder, follow these steps:
1. Base Area:
The base of the cylinder is a circle with radius \( r = 5 \) cm.
\[
\text{Base Area} = \pi r^2 = \pi \times 5^2 = 25\pi \text{ cm}^2
\]
2. Curved Surface Area:
The curved surface area of the cylinder is given by:
\[
\text{Curved Surface Area} = 2 \pi r h = 2 \pi \times 5 \times 10 = 100\pi \text{ cm}^2
\]
3. Ratio of Base Area to Curved Surface Area:
\[
\text{Ratio} = \frac{\text{Base Area}}{\text{Curved Surface Area}} = \frac{25\pi}{100\pi} = \frac{25}{100} = \frac{1}{4}
\]
So, the ratio of the base area to the curved surface area is:
C. 1:4