Write the following expression as a single fraction: \(\frac{2}{2x-3} + \frac{1}{2-x}\)
A. \(\frac{7}{(2x-3)(2-x))}\) B. \(\frac{4x+1}{(2x-3)(2-x)}\) C. \(\frac{1}{(2x-3)(2-x)}\) D. \(\frac{7-4x}{(2x-3)(2-x)}\)
Correct Answer: C
Explanation
To combine the two fractions \(\frac{2}{2x-3} + \frac{1}{2-x}\) into a single fraction, follow these steps:
1. Notice that \(2 - x\) is the same as \(-(x - 2)\) or \(-(2x - 3)\) with a sign change. So, \(\frac{1}{2-x}\) can be rewritten as \(-\frac{1}{2x-3}\).
2. Rewrite the expression using this simplification: \[ \frac{2}{2x-3} + \frac{1}{2-x} = \frac{2}{2x-3} - \frac{1}{2x-3} \]
3. Now, combine the fractions since they have a common denominator: \[ \frac{2 - 1}{2x-3} = \frac{1}{2x-3} \]
Therefore, the correct answer is C. \(\frac{1}{(2x-3)(2-x)}\).