The volume of the pipe is equal to the area of the cross section and length.
let outer and inner radii be R and r respectively.
Area of the cross section = (R² - r²)
where R = 6 and r = 6 - 1
= 5cm
Area of the cross section = (6² - 5²)$\pi$ = (36 - 25)$\pi$cm sq
vol. of the pipe = $\pi$ (R² - r²)L where length (L) = 10
volume = 11$\pi$ x 10
= 110$\pi$cm³