Sum of interior angles of any polygon is (2n - 4) right angle; n angles of the nonagon = 9
where 3 are equal and 6 other angles = 1110^o
( 2 x 9 - 4)90^o = (18 - 4)90^o
= 14 x 90^o = 1260^o
9 angles = 12600, 6 angles = 1110^o
Remaining 3 angles = 1260^o - 1110^o = 150^o
size of one of the3 angles \(\frac{150}{3}\) = 50^o