A. x = -1 \(\pm\) \(\frac{\sqrt{3}}{3}\) B. x = -1 \(\pm\) \(\frac{\sqrt{15}}{3}\) C. x = -2 \(\pm\) 2 D. x = 3 \(\pm\) \(\frac{\sqrt{3}}{15}\)
Correct Answer: B
Explanation
3x2 + 6x - 2 = 0 Using almighty formula i.e. x = \(\frac{b \pm \sqrt{b^2 - 4ac}}{2a}\) a = 3, b = 6, c = -2 x = \(\frac{-6 \pm \sqrt{6^2 - 4(3)(-2)}}{2(3)}\) x = \(\frac{-6 \pm \sqrt{36 +Â 24}}{6}\) x = \(\frac{-6 \pm \sqrt{60}}{6}\) x = \(\frac{-6 \pm \sqrt{4 \times 15}}{6}\) x = \(-1 \pm \frac{\sqrt{15}}{3}\)