In the figure, PQ is the tangent from P to the circle QRS with SR as its diameter. If QRS = \(\theta\)oand RQP = \(\phi\)o, which of the following relationships between \(\theta\)o and \(\phi\)o is correct
A. \(\theta\)o + \(\phi\)o = 902 B. \(\phi\)o = 902 - 2\(\theta\)o C. \(\theta\)o = \(\phi\)o D. \(\phi\)o = 2\(\theta\)o E. \(\theta\)o + 2\(\phi\)o
Correct Answer: E
Explanation
180 - \(\phi\)o = \(\theta\)o + \(\phi\)o (Sum of opposite interior angle equal to its exterior angle)