Which of the formula below represents the general terms of the following set of numbers(-1, \(\frac{2}{3}\), -\(\frac{1}{2}\), \(\frac{2}{5}\)......) for n = 1, 2, 3, 4.......?
A. \(\frac{2}{n + 1}\) B. (-1)n + 1 \(\frac{2}{n + 1}\) C. (-1)n \(\frac{2}{n + 1}\) D. \(\frac{n}{2n - 1}\) E. (-1)n\(\frac{n}{2n - 1}\)
Correct Answer: C
Explanation
(-1, \(\frac{2}{3}\), -\(\frac{1}{2}\), \(\frac{2}{5}\)......) nthterm is (-1)n\(\frac{2}{n + 1}\) Since (-1)n will always be negative for n = odd
