A box contains two red balls and four blue balls. A ball is drawn at random from the box and then replaced before a second ball is drawn. Find the probability of drawing two red balls.
A. \(\frac{2}{3}\) B. \(\frac{1}{3}\) C. \(\frac{1}{4}\) D. \(\frac{1}{9}\)
Correct Answer: D
Explanation
Total number of balls = 2 + 4 = 6 P(of picking a red ball) = \(\frac{2}{6}\) = \(\frac{1}{3}\) P(of picking a blue ball) = \(\frac{4}{6}\) = \(\frac{2}{3}\) With replacement, P( picking two red balls) = \(\frac{1}{3}\) × \(\frac{1}{3}\) = \(\frac{1}{9}\)
