If P = [\(\frac{Q(R - T)}{15}\)] \(\frac{1}{3}\) make T the subject of the relation
A. T = \(\frac{R + P^3}{15Q}\) B. T = \(\frac{R - 15P^3}{Q}\) C. T = \(\frac{R - 15P^3}{Q}\) D. T = \(\frac{15R - Q}{P^3}\)
Correct Answer: C
Explanation
Taking the cube of both sides of the equation give P\(^3\) = \(\frac{Q(R - T)}{15}\) Cross multiplying 15P\(^3\) = Q(R - T) Divide both sides by Q \(\frac{15P^3}{Q}\) = R - T Rearranging gives T = R - \(\frac{15P^3}{ Q}\) = \(\frac{RQ - 15P^3}{Q}\)
