\(\begin{array}{c|c} Numbers & 1 & 2 & 3 & 4 & 5 & 6 \\ \hline Frequency & 18 & 22 & 20 & 16 & 10 & 14 \end{array}\) The table above represents the outcome of throwing a die 100 times. What is the probability of obtaining at least a 4?
A. \(\frac{1}{5}\) B. \(\frac{1}{2}\) C. \(\frac{2}{5}\) D. \(\frac{3}{4}\)
Correct Answer: C
Explanation
Let E demote the event of obtaining at least a 4 Then n(E) = 16 + 10 + 14 = 40 Hence, prob (E) = \(\frac{n(E)}{n(S)}\) \( = \frac{40}{100}\) \( = \frac{2}{5}\)
