A room is 12m long, 9m wide and 8m high. Find the cosine of the angle which a diagonal of the room makes with the floor of the room.
A. \(\frac{15}{17}\) B. \(\frac{9}{17}\) C. \(\frac{8}{15}\) D. \(\frac{12}{17}\)
Correct Answer: A
Explanation
Given length of the room = 12m; breadth = 9m and height = 8m. The room is a cuboid in shape, therefore the length of the diagonal = \(\sqrt{l^2 + b^2 + h^2}\) = \(\sqrt{12^2 + 9^2 + 8^2}\) =\(\sqrt{289}\) = 17m. The diagonal makes an angle with the diagonal of the floor: \(\sqrt{12^2 + 9^2}\) = \(\sqrt{225}\) = 15m The cosine of the angle that the diagonal makes with the floor (\(\theta\)) = \(\frac{15}{17}\). Â