Profit (P) = 10\(_x\) − \(_x\)2
 Maximum profit can be achieved when the differential of profit with respect to number of bags(x) is 0
 i.e. \(\frac{dp}{dx}\) = 0
 \(\frac{dp}{dx}\) = 10 - 2x = 0
 10 = 2x
 Then x = \(\frac{10}{2}\) = 5
 Answer is C