(a)

x	-5	-4	-3	-2	-1	0	1	2	3	4
y	35	18	5	-4	-9	-10	-7	0	11	26

(b)
(c)(i) 2x\(^{2}\) + x = 10 \(\equiv\) 2x\(^{2}\) + x - 10 = 0
Thus, the solution of 2x\(^{2}\) + x - 10 = 0 are the values of x at which the curve cuts the x- axis.
x = -2.5 or x = 2.
(ii) 2x\(^{2}\) + x - 10 = 2x
To solve the given equation, we first draw the graph of y = 2x: when x = -2, y = 2(-2) = -4; when x = 3, y = 2(3) = 6.
The values of x at which y = 2x\(^{2}\) + x - 10 and y = 2x intersect give the solution of 2x\(^{2}\) + x - 10 = 2x.
These are x = -2 or x = 2.5.