(a)

x	0°	30°	60°	90°	120°	150°	180°	210°	240°	270°	300°	330°	360°
y	2.0	3.2	3.6	3.0	1.6	-0.2	-2.0	-3.2	-3.6	-3.0	-1.6	0.2	2.0

(b)
(c)(i) The equation, $3\sin x+2\cos x=0$ has solution where the curve cuts the x- axis, i.e. at A(x = 147°) and B(x = 325.5°).
(ii)First, rearrange $2+2\cos x+3\sin x=0$ to have the main graph content $3\sin x+2\cos x$ on one side of the equation; i.e. $3\sin x+2\cos x=-2$.
Add the line $y=-2$ to the graph. The line intersects the curve at the points (x = 180°) and (x = 292.5°). Hence, these are the solutions.