If a number is selected at random from each of the sets p = {1, 2, 3} and Q = {2, 3, 5}, find the probability that the sum of the numbers is prime
A. \(\frac{5}{9}\) B. 1\(\frac{4}{9}\) C. \(\frac{1}{3}\) D. \(\frac{2}{9}\)
Correct Answer: C
Explanation
p = { 1, 2, 3} Q = {2, 3, 5} prob(prime number) = prob(1 and 2) or = prob(2 and 3) or = prob(3 and 2) There are three possibilities of the sum being prime Total possibility = 9 probability(sum being prime) = \(\frac{3}{9}\) = \(\frac{1}{3}\)
