Subtract \(\frac{1}{2}\)(a - b - c) from the sum of \(\frac{1}{2}\)(a - b + c) and \(\frac{1}{2}\)
(a + b - c)
A. \(\frac{1}{2}\) (a + b + c)
B. \(\frac{1}{2}\) (a - b - c)
C. \(\frac{1}{2}\) (a - b + c)
D. \(\frac{1}{2}\) (a + b - c)
Correct Answer: A
Explanation
\(\frac{1}{2}\)(a - b + c) + \(\frac{1}{2}\)(a + b - c) - [\(\frac{1}{2}\) (a - b - c)]
\(\frac{1}{2}a - \frac{1}{2}b + \frac{1}{2}c + \frac{1}{2}a + \frac{1}{2}b - \frac{1}{2}c - \frac{1}{2}a + \frac{1}{2}b + \frac{1}{2}c\)
= \(\frac{1}{2}a + \frac{1}{2}b + \frac{1}{2}c\)
= \(\frac{1}{2}(a + b + c)\)
