(a)(i) R is the required region.
(iii) Coordinates of the point of intersection of the two graphs = (1.1, 3.8)
(b) Assuming \(y - \frac{3x}{4} = 3\)
If x = 0, \(y - \frac{3}{4}(0) = 3 \implies y = 3\)
If y = 0, \(0 - \frac{3}{4}x = 3 \implies -3x = 12 ; x = - 4\)

x	0	-4
y	3	0

Assuming \(y + 2x = 6\)
If x = 0, \(y + 2(0) = 6 \implies y = 6\)
If y = 0, \(0 + 2x = 6 \implies 2x = 6 ; x = 3\)

x	0	3
y	6	0

(b) \((x + 2)(x + c) = x^{2} + 2x + cx + 2c\)
\(x^{2} + (2 + c)x + 2c = x^{2} + bx + 18\)
\( 2c = 18 ; c = 9\)
\(b = 2 + c = 2 + 9 = 11\)
(b, c) = (11, 9).