L + 30^o - 180^o(Sum of < s on straight line)
L = 180^o - 30^o = 150^o
L = q = 150^o(opposite < s are equal)
y = b = 30^o(alt. < s)
b + c = 180^o(sum of < s on str. line)
30^o + c 180
c = 180 - 30
c = 150^o
b = a = 30^o (opp < s are equal)
c = d = 150^o (opp < s are equal)
a + k + 70^o = 180^o (sum of < s on \(\bigtriangleup\))
30^o + k + 70^o = 180
k + 100^o = 180
k = 180 - 100
k = 80^o
x + 80^o = 180(sum of < s on straight line)
x = 180^o - 80^o
x = 100^o