Alfred spent \(\frac{1}{4}\) of his money on food, \(\frac{1}{3}\) on clothing and save the rest. If he saved N72,20.00, how much did he spend on food?
A. N43,200.00 B. N43,000.00 C. N42,200.00 D. N40,000.00
Correct Answer: A
Explanation
let the total amount be Nx i.e (\(\frac{1}{4}\))x + (\(\frac{1}{3}\))x + 72,000 = x \(\frac{x}{4} + \frac{x}{4} + 72,000 = x\) \(\frac{3x + 4x + 86,400}{12} = x\) cross multiply to clear fraction 12x = 3x + 4x + 86,400 12x - 7x = 86,400 5x = 86,400 x - \(\frac{86,400}{5}\) = 172,800 amount spent on food = \(\frac{1}{4} \times 172,800\) = N43,200
