(a)



\(\frac{FM}{FB} = \tan 35\)
\(\therefore \frac{FM}{120} = \tan 35\)
\(FM = 120 \tan 35 \)
= \(120 \times 0.7002\)
= \(84.024 m\)
Therefore, the height of the cliff = \(2 \times 84.024 = 168.048m\)
(b) Distance between P and Q = x km
Speed for 1st motorist = 60 km/h
\(\therefore \text{1st motorist's time} = \frac{x}{60} hrs\)
Speed for 2nd motorist = 80 km/h
\(\therefore \text{2nd motorist's time} = \frac{x}{80} hrs\)
\(\frac{x}{60} - \frac{x}{80} = \frac{30}{60}\)
\(\frac{4x - 3x}{240} = \frac{1}{2}\)
\(\frac{x}{240} = \frac{1}{2} \implies 2x = 240\)
\(x = 120 km\).