A box contains 5 red, 3 green and 4 blue balls. A boy is allowed to take away two balls from the box. What is the probability that the two balls are red?
A. \(\frac{5}{33}\) B. \(\frac{5}{36}\) C. \(\frac{103}{132}\) D. \(\frac{31}{36}\)
Correct Answer: A
Explanation
Total number of balls = 5 + 3 + 4 = 12 balls P(first ball is red) = \(\frac{5}{12}\) P(second ball is red) = \(\frac{4}{11}\) \(\therefore\) P(both balls are red) = \(\frac{5}{12} \times \frac{4}{11}\) = \(\frac{5}{33}\)
