Water flows from a tap into cylindrical container at the rate 5πcm\(^3\) per second. If the radius of the container is 3cm, calculate the level of water in the container at the end of 9 seconds.
A. 2cm B. 5cm C. 8cm D. 15cm
Correct Answer: B
Explanation
Volume of water after 9 seconds = \(5\pi \times 9 = 45\pi cm^3\) Volume of cylinder = \(\pi r^2 h\) \(\therefore \pi r^2 h = 45\pi\) \(\pi \times 3^2 \times h = 45\pi\) \(\implies 9h = 45 \) \(h = 5 cm\) (where h = height of the water after 9 secs)
