(a) Sample space for a pair of fair dice = 36 results

+	1	2	3	4	5	6
1	2	3	4	5	6	7
2	3	4	5	6	7	8
3	4	5	6	7	8	9
4	5	6	7	8	9	10
5	6	7	8	9	10	11
6	7	8	9	10	11	12

Total with sum at least 9 = 10
P(sum at least 9) = \(\frac{10}{36} = \frac{5}{18}\)
(b) P(civil servant owns a car) = \(\frac{1}{6}\)
P(civil servant owns no car) = \(\frac{5}{6}\)
(i) P(A and B own a car) = \(\frac{1}{6} \times \frac{1}{6} = \frac{1}{36}\)
(ii) P(C and D, only one owns a car) = P(C owns, not D) + P(not C but D owns)
= \((\frac{1}{6} \times \frac{5}{6}) + (\frac{5}{6} \times \frac{1}{6})\)
= \(\frac{5}{36} + \frac{5}{36}\)
= \(\frac{10}{36} = \frac{5}{18}\)
(iii) P(of X, Y and Z, only one owns a car) = P(X owns a car, not Y, not Z) + P(not X, Y owns a car, not Z) + P(not X, not Y, Z owns a car)
= \(3(\frac{1}{6} \times \frac{5}{6} \times \frac{5}{6})\)
= \(3 \times \frac{25}{216}\)
= \(\frac{25}{72}\)