Draw the table of value such that \(-x + 5y \leq 10 \implies -x + 5y = 10\)
\(\implies 5y = 10 + x \)
\(y = 2 + \frac{x}{5}\)
and \(3x - 4y \leq 8 \implies 3x - 4y = 8\)
\(y = -2 + \frac{3x}{4}\)
Table of value for \(-x + 5y = 10\)

x	-4	0	4
y	1.2	2	2.8

Table of value for \(3x - 4y = 8\)

x	-4	0	4
y	-5	-2	1