Let the total number of items in the man's shop = $y$

Number of Brand A's items in the man's shop = $\frac{1}{9}y$

Remaining items = 1 - $\frac{1}{9}y=\frac{8}{9}y$

Number of Brand B's items in The man's shop = $\frac{5}{8}of\frac{8}{9}y=\frac{5}{9}y$

Total of Brand A and Brand B's items = $\frac{1}{9}y+\frac{5}{9}y=\frac{2}{3}y$

Number of Brand C's items in the man's shop = 1 - $\frac{2}{3}y=\frac{1}{3}y$

$⟹\frac{1}{3}y$ = 81 (Given)

$⟹y$ = 81 x 3 = 243

∴ The total number of items in the man's shop = 243

∴ Number of Brand B's items in the man's shop = $\frac{5}{9}$ x 243 = 135

∴ The number of more Brand B items than Brand C = 135 - 81 =54