Change of subject of formula - Jamb Mathematics Past Questions and Answers

Question 41:

• JAMB 2011

Make R the subject of the formula if T = \(\frac {KR^2 + M}{3}\)

A. \(\sqrt\frac{3T - K}{M}\)
B. \(\sqrt\frac{3T - M}{K}\)
C. \(\sqrt\frac{3T + K}{M}\)
D. \(\sqrt\frac{3T - K}{M}\)

Question 42:

• JAMB 2012

Make 'n' the subject of the formula if w = \(\frac{v(2 + cn)}{1 - cn}\)

A. \(\frac{1}{c}(\frac{w - 2v}{v + w})\)
B. \(\frac{1}{c}(\frac{w - 2v}{v - w})\)
C. \(\frac{1}{c}(\frac{w + 2v}{v - w})\)
D. \(\frac{1}{c}(\frac{w + 2v}{v + w})\)

Question 43:

• JAMB 2013

If S = \(\sqrt{t^2 - 4t + 4}\), find t in terms of S

A. S² - 2
B. S + 2
C. S - 2
D. S² + 2

Question 44:

• JAMB 2014

If gt² - k - w = 0, make g the subject of the formula

A. \(\frac{k + w}{t^2}\)
B. \(\frac{k - w}{t^2}\)
C. \(\frac{k + w}{t}\)
D. \(\frac{k - w}{t}\)

Question 45:

• JAMB 2015

Make x the subject of the equation
s = 2 + \(\frac{t}{5} \)(x + 3/5y)

A. X = 5[(s − 2) ÷ t] + 3yt
B. X = 25[(s − 2) ÷ t] − 3ty
C. X = [1 ÷ (s − 2)3ty]
D. X = [5(s − 2) 2 ÷ 3ty] x t