Coordinate Geometry - Jamb Mathematics Past Questions and Answers

Question 26:

• JAMB 2014

In the figure above, what is the equation of the line that passes the y-axis at (0,5) and passes the x-axis at (5,0)?

A. Y = x + 5
B. Y = -x + 5
C. Y = x - 5
D. Y = -x - 5

Question 27:

• JAMB 2013

Find the equation of the perpendicular bisector of the line joining P(-2, 3) to Q(-5, 1)

A. 8y + 14x + 13 = 0
B. 8y - 14x + 13 = 0
C. 8y - 14x - 13 = 0
D. 8y + 14x - 13 = 0

Question 28:

• JAMB 2013

In triangle PQR, q = 8 cm, r = 6 cm and cos P = \(\frac{1}{12}\). Calculate the value of p.

A. \(\sqrt{108}\) cm
B. 9 cm
C. \(\sqrt{92}\) cm
D. 10 cm

Question 29:

• JAMB 1978

The number of telephone calls N between two cities A and B varies directly as the population P\(_{A}\), P\(_B\) respectively and inversely as the square of the distance D between A and B. Which of the following equations represents this relation?

A. N = \(\frac{kp_A}{D^2} + {cp_B}{D^2}\)
B. N = \(\frac{k P_{A} P_{B} }{D^2}\)
C. N = \(\frac{kD_AP_D}{B^2}\)
D. N = \(\frac{kD^2_AP_D}{B}\)

Question 30:

• JAMB 1978

A triangle has angles 30o, 15o and 135o. The side opposite to the angle 30o is length 6cm. The side opposite to the angle 135o is equal to

A. 12cm
B. 6cm
C. 6\(\sqrt{2}\)cm
D. 12\(\sqrt{2}\)cm