Welcome to Schoolngr.com

Home   School   News   C B T   Classroom
Monday, 25 November 2024

RegisterLogin

Surds - Jamb Mathematics Past Questions and Answers

Exam year:
Question type:
Topics:

Jamb Mathematics Past Questions

Jamb Past Questions and Answers on Surds

Question 21:


Rationalize the expression \(\frac{1}{\sqrt{2} + \sqrt{5}}\)

A. \(\frac{1}{3}\)(\(\sqrt{5} - \sqrt{2}\)
B. \(\frac{\sqrt{2}}{3}\) + \(\frac{\sqrt{5}}{5}\)
C. \(\sqrt{2} - \sqrt{5}\)
D. 5(\(\sqrt{2} - \sqrt{5}\)
E. \(\frac{1}{3}\)(\(\sqrt{2} - \sqrt{5}\)


Question 22:


Rationalize the expression \(\frac{1}{\sqrt{2} + \sqrt{5}}\)

A. \(\frac{1}{3}\)(\(\sqrt{5} - \sqrt{2}\)
B. \(\frac{\sqrt{2}}{3}\) + \(\frac{\sqrt{5}}{5}\)
C. \(\sqrt{2} - \sqrt{5}\)
D. 5(\(\sqrt{2} - \sqrt{5}\)
E. \(\frac{1}{3}\)(\(\sqrt{2} - \sqrt{5}\)


Question 23:


Rationalize \(\frac{5\sqrt{7} - 7\sqrt{5}}{\sqrt{7} - \sqrt{5}}\)

A. -2 \sqrt{35}\)
B. 4\sqrt{7}\) - 6\(\sqrt{5}\)
C. -\(\sqrt{35}\)
D. 4\sqrt{7}\) - 8\(\sqrt{5}\)
E. \(\sqrt{35}\)


Question 24:


\((\sqrt[4]{3} + \sqrt[4]{2})(\sqrt[4]{3} - \sqrt[4]{2})(\sqrt{3} + \sqrt{2})\) is equal to

A. 1
B. (\(\sqrt{2} + 4\sqrt{2}\))
C. (6\(\sqrt{2}\)
D. 8


Question 25:


Simplify \((\frac{1}{\sqrt{5} + \sqrt{3}} - \frac{1}{\sqrt{5} - \sqrt{3}}) \times \frac{1}{\sqrt{3}}\)

A. \(\frac{\sqrt{3}}{\sqrt{5}}\)
B. \(\frac{2 \sqrt{3}}{7}\)
C. -2
D. -1






AboutContact usBack to Top
...

Disclaimer
All Views, Names, Acronyms, Trademarks, Expressed on this website are those of their respective owners. Please note that www.schoolngr.com is not affiliated with any of the institutions featured in this website. It is always recommended to visit an institutions or sources official website for more information. In the same vein, all comments placed here do not represent the opinion of schoolngr.com


SCHOOLNGR - © 2020 - 2024 - Tayo Hammed | Terms Of Service | Copyright | Privacy Policy