Change of subject of formula - Jamb Mathematics Past Questions and Answers

Question 21:

• JAMB 1984

If pq + 1 = q² and t = \(\frac{1}{p}\) - \(\frac{1}{pq}\) express t in terms of q

A. \(\frac{1}{p - q}\)
B. \(\frac{1}{q - 1}\)
C. \(\frac{1}{q + 1}\)
D. 1 + 0
E. \(\frac{1}{1 - q}\)

Question 22:

• JAMB 1985

Write h in terms of a, b, c, d if a = \(\frac{b(1 - ch)}{a - dh}\)

A. H = \(\frac{a - b}{ad}\)
B. H = \(\frac{1 - b}{ad - bc}\)
C. H = \(\frac{(a - b)^2}{ad - bc}\)
D. H = \(\frac{a - b}{ad - bc}\)
E. H = \(\frac{b - a}{ab - dc}\)

Question 23:

• JAMB 1986

make U the subject of the formula S = \(\sqrt{\frac{6}{u} - \frac{w}{2}}\)

A. U = \(\frac{12}{2s^2}\)
B. U = \(\frac{12}{2s+ w}\)
C. U = \(\frac{12}{2s^2 + w}\)
D. U = \(\frac{12}{2s^2}\) + w

Question 24:

• JAMB 1987

Make y the subject of the formula Z = x\(^2\) + \(\frac{1}{y^3}\)

A. Y = \(\frac{1}{(Z - x^2)^3}\)
B. Y = \(\frac{1}{(Z + x^2)^{\frac{1}{3}}}\)
C. Y = \(\frac{1}{(Z - x^2)^{\frac{1}{3}}}\)
D. Y = \(\frac{1}{\sqrt[3]{Z} - \sqrt[3]{x^2}}\)

Question 25:

• JAMB 1989

Make R the subject of the fomula S = \(\sqrt{\frac{2R + T}{2RT}}\)

A. R = \(\frac{T}{(TS^2 + 1)}\)
B. R = \(\frac{T}{2(TS^2 - 2)}\)
C. R = \(\frac{T}{2(TS^2 + 1)}\)
D. R = \(\frac{R}{2(TS^2 + 1)}\)