Change Of Subject Of Formula - Mathematics Jamb Past Questions and Answers

Question 16 :

• JAMB 1980

Make c the subject of formula v = 1 - \(\frac{a}{5}\)(b + \(\frac{3c}{7}\))

A. [\(\frac{7}{3}\) + \(\frac{5}{a}\)(v - 1)] + b
B. [\(\frac{7b}{3}\) + \(\frac{5}{a}\)(v - 1)]
C. \(\frac{7}{3}\)[b + \(\frac{5}{a}\)(v - 1)]
D. \(\frac{7}{3}\)[b + \(\frac{5v - 1}{a}\)]

Question 17 :

• JAMB 1981

If b = a + cp and r = ab + \(\frac{1}{2}\)cp², express b² in terms of a, c, r.

A. B² = aV + 2cr
B. B² = ar + 2c²r
C. B² = a² = \(\frac{1}{2}\) cr²
D. B² = \(\frac{1}{2}\)ar² + c
E. B² = 2cr - a²

Question 18 :

• JAMB 1981

In the figure, find x in terms of a, b and c.

A. A + b + c
B. 180^o - (a + b + c)
C. A - b - c
D. A + b
E. A + c

Question 19 :

• JAMB 1982

Solve for x, If \(\frac{\frac{2}{x}}{\frac{p^2 + p^2}{p^2 + p^2}}\) = m

A. \(\frac{4pq}{m(p + q)}\)
B. \(\frac{2p^2q^2}{m(q^2 + p^2)}\)
C. \(\frac{2pq}{m(q^2 + p^2)}\)
D. \(\frac{2p^2q^2}{m(p^2)}\)

Question 20 :

• JAMB 1983

Make T the subject of the equation \(\frac{av}{1 - v}\) = \(\sqrt{\frac{2v + T}{a + 2T}}\)

A. T = \(\frac{3av}{1 - v}\)
B. T = \(\frac{1 + v}{2a^2v^3}\)
C. T = \(\frac{2v(1 - v)^3 - a^4v^3}{2a^3v^3 + (1 - v)^2}\)
D. \(\frac{2v(1 - v)^3 - a^4 v^3}{2a^3v^ 3 - (1 - v)^3}\)