Change of subject of formula - Jamb Mathematics Past Questions and Answers

Question 11:

• JAMB 2015

Make x the subject of the equation
s = 2 + \(\frac{t}{5} \)(x + 3/5y)

A. X = 5[(s − 2) ÷ t] + 3yt
B. X = 25[(s − 2) ÷ t] − 3ty
C. X = [1 ÷ (s − 2)3ty]
D. X = [5(s − 2) 2 ÷ 3ty] x t

Question 12:

• JAMB 2014

If gt² - k - w = 0, make g the subject of the formula

A. \(\frac{k + w}{t^2}\)
B. \(\frac{k - w}{t^2}\)
C. \(\frac{k + w}{t}\)
D. \(\frac{k - w}{t}\)

Question 13:

• JAMB 2013

If S = \(\sqrt{t^2 - 4t + 4}\), find t in terms of S

A. S² - 2
B. S + 2
C. S - 2
D. S² + 2

Question 14:

• JAMB 1978

Simplify \(\frac{a - b}{a + b}\) - \(\frac{a + b}{a - b}\)

A. \(\frac{4ab}{a - b}\)
B. \(\frac{-4ab}{a^2 - b^2}\)
C. \(\frac{-4ab}{a^{-2} - b}\)
D. \(\frac{4ab}{a^{-2} - b^{-2}}\)

Question 15:

• JAMB 1979

Make x the subject of the equation a(b + c) + \(\frac{5}{d}\) - 2 = 0

A. C = \(\frac{2d - 5 - b}{ad}\)
B. C = \(\frac{2d - 5 - abd}{ad}\)
C. C = \(\frac{2d - 5 - ab}{ad}\)
D. C = \(\frac{5 - 2d - b}{ad}\)