Polynomials - Jamb Mathematics Past Questions and Answers

Question 76:

• JAMB 1982

Seven years ago, the age of a father was three times that of his son, but in six years time the age of the son will be half that of his father, representing the present ages of the father and son by x and y, respectively, the two equations relating x and y are

A. 3y - x = 0; 2y - x = 0
B. 3y - x = 14; x - 2y = 6
C. 3y - x =7; x - 2y = 6
D. 3y - x = 14; y - 2x = 6
E. X + 3y = 7; x = 2y = 12

Question 77:

• JAMB 1982

The factors of 6x - 5 - x2 are

A. -(x + 3)(x + 2)
B. (x + 5)(x + 1)
C. (x - 5)(1 - x)
D. (x + 1)(x + 5)

Question 78:

• JAMB 1982

The solution of the quadratic equation bx2 + cx + a = 0 is given by

A. X = b \(\pm\) \(\frac{\sqrt{b^2 - 4ac}}{2a}\)
B. X = c \(\pm\) \(\frac{\sqrt{b^2 - 4ab}}{2b}\)
C. X = -c \(\pm\) \(\frac{\sqrt{c^2 - 4ab}}{2b}\)
D. X = -b \(\pm\) \(\frac{\sqrt{b^2 - 4ac}}{2b}\)

Question 79:

• JAMB 1982

The graphical method of solving the equation x3 + 3x2 + 4x - 28 = 0 is by drawing the graphs of the curves

A. Y = x³ and y = 3x² + x - 28
B. Y = x³ + 3x² + 4x + 4 and the line y = \(\frac{28}{x}\)
C. Y = x³ + 3x² + 4x and y
D. Y = x² + 3x + 4 and y = \(\frac{28}{x}\)
E. Y = x² + 3x + 4 and line y = 28x

Question 80:

• JAMB 1982

Solve for x, If \(\frac{\frac{2}{x}}{\frac{p^2 + p^2}{p^2 + p^2}}\) = m

A. \(\frac{4pq}{m(p + q)}\)
B. \(\frac{2p^2q^2}{m(q^2 + p^2)}\)
C. \(\frac{2pq}{m(q^2 + p^2)}\)
D. \(\frac{2p^2q^2}{m(p^2)}\)