Jamb Mathematics Past Questions and Answers

Question 766:

• JAMB 1984

Simplify \(\frac{(\frac{2}{3} - \frac{1}{5}) - \frac{1}{3} \text{of} \frac{2}{5}}{3 - \frac{1}{1 \frac{1}{2}}}\)

A. \(\frac{1}{7}\)
B. 7
C. \(\frac{1}{3}\)
D. 3

Question 767:

• JAMB 1984

Simplify \(\frac{(\frac{2}{3} - \frac{1}{5}) - \frac{1}{3} \text{of} \frac{2}{5}}{3 - \frac{1}{1 \frac{1}{2}}}\)

A. \(\frac{1}{7}\)
B. 7
C. \(\frac{1}{3}\)
D. 3

Question 768:

• JAMB 1984

\(\frac{0.0001432}{1940000}\) = k x 10ⁿ where 1 \(\leq\) k < 10 and n is a whole number. The values K and n are

A. 7.381 qnd -11
B. 2.34 and 10
C. 3.871 and 2
D. 7.831 and -11

Question 769:

• JAMB 1984

P sold his bicycle to Q at a profit of 10%. Q sold it to R for N209 at a loss of 5%. How much did the bicycle cost P?

A. N200
B. N196
C. N180
D. N205
E. N150

Question 770:

• JAMB 1984

If the price of oranges was raised by \(\frac{1}{2}\)k per orange. The number of oranges a customer can buy for N2.40 will be less by 16. What is the present price of an orange?

A. 2\(\frac{1}{2}\)
B. \(\frac{2}{15}\)
C. 5\(\frac{1}{3}\)
D. 20