Mathematics 2018 Jamb Past Questions and Answers

Question 66 :

• JAMB 2018

If y = 23\(_{five}\) + 101\(_{three}\) , find y, leaving your answer in base two

A. 1110
B. 10111
C. 11101
D. 111100

Question 67 :

• JAMB 2018

Solve for t in the equation \(\frac{3}{4}\)t + \(\frac{1}{3}\)(21 - t) = 11

A. \(\frac{9}{13}\)
B. \(\frac{7}{13}\)
C. 5
D. 9\(\frac{3}{5}\)

Question 68 :

• JAMB 2018

A school girl spends \(\frac{1}{4}\) of her pocket money on books and \(\frac{1}{3}\) on dress. What fraction remains?

A. \(\frac{5}{6}\)
B. \(\frac{7}{12}\)
C. \(\frac{5}{12}\)
D. \(\frac{1}{6}\)

Question 69 :

• JAMB 2018

If \(\frac{x}{a + 1}\) + \(\frac{y}{b}\) = 1. Make y the subject of the relation.

A. \(\frac{b(a + 1 - x)}{a + 1}\)
B. \(\frac{a + 1}{b(a - x + 1)}\)
C. \(\frac{a(b - x + 1)}{b + 1}\)
D. \(\frac{b}{a(b - x + 1)}\)

Question 70 :

• JAMB 2018

The probabilities that John and James pass an examination are \(\frac {3}{4}\)and \(\frac {3}{5}\) respectively. Find the probability of both boys failing the examination.


A. \(\frac {1}{10}\)
B. \(\frac {2}{10}\)
C. \(\frac {9}{20}\)
D. \(\frac {11}{20}\)