Chemical Equilibrium - Chemistry Jamb Past Questions and Answers

Question 16 :

• JAMB 1997

mE + nF → pG + qH. In the equation above, the equilibrium constant is given by?

A. (E)^m(F)ⁿ/ (G)ⁿ(H)^q
B. (E)(F) / (G)(H)
C. (G)^p(H)^q / (E)^m(F)ⁿ
D. (G)(H) / (E)(F)

Question 17 :

• JAMB 1998

2Cl^2(g) + 2H₂O_(g) 4HCl_(g) + O_2(g)
∆H° = +115KJ mol^-1. In the above equilibrium reaction, a decrease in temperature will?

A. Favour the reverse reaction
B. Favour the forward reaction
C. Have no effect on the equilibrium state
D. Double the rate of the reverse raection

Question 18 :

• JAMB 1999

N₂O_4(g) ↔ 2NO_2(g). Increase in total pressure of the equilibrium reaction above will

A. Produce more of NO_2(g) in the mixture
B. Convert all of N₂O_4(g) to NO_2(g)
C. Have no effect on the concentrations of NO_2(g)and N₂O_4(g)
D. Produce more of N₂O_4(g) in the mixture

Question 19 :

• JAMB 2000

For a reaction in equilibrium, the species involved in the equilibrium constant expression are

A. Gaseous and solid species
B. Liquid and solid species
C. Solid and dissolved species
D. Gaseous and dissolved species

Question 20 :

• JAMB 2001

2SO_2(g) + O_2(g) ↔ 2SO_3(g)
ΔH = -189 kJ mol^-1
The equilibrium constant for the reaction above is increased by

A. Increasing the temperature of the system
B. Increase the pressure of the system
C. The addition of a catalyst to the system
D. Increasing the surface area of the vessel