Electrolysis - Jamb Chemistry Past Questions and Answers

Question 86:

• JAMB 2011

Given that M is the mass of a substance deposited during electrolysis and Q is the quantity of electricity consumed, then Faraday's first law can be written as
[Electrochemical equivalent]

A. M = E/Q
B. M = EQ
C. M = Q/E
D. M = E/2Q

Question 87:

• JAMB 2012

What number of moles of Cu 2+ will be deposited by 360 coulombs of electricity?
[f = 96500 C mol -1]

A. 5.36 x 10 ^-4 mole
B. 1. 87 x 10 10 ^-3 mole
C. 9. 35 x 10 ^-4 mole
D. 3. 73 x 10 ^-3

Question 88:

• JAMB 2013

In an electrochemical cell, polarization is caused by

A. Chlorine
B. Oxygen
C. Tetaoxsulphate (Vl) acid
D. Hydrogen

Question 89:

• JAMB 2014

Calculate the quantity of electricity in coulombs required to liberate 10g of copper from a copper compound
[Cu=64, F = 96500 Cmol^-1]

A. 32395.5
B. 30156.3
C. 60784.5
D. 15196.5

Question 90:

• JAMB 2014

How many faraday of electricity is required to produce 0.25 mole of copper?

A. 1.00F
B. 0.01F
C. 0.05F
D. 0.50F