A body is projected with a velocity \(\mathrm{Vms}^{-}\), inclined at an angle \(\beta\) to the vertical. Which of the following gives the CORRET expression for the horizontal component of velocity \(\mathrm{V}_x\) after time t?
A. V cos \(\beta\) B. \(V \sin \beta\) C. \(\mathrm{Vg} \cos \beta\) D. Vtsin \(\beta\)
Correct Answer: B
Explanation
\(V_x=V \cos \left(90^{\circ}-\beta\right)\) and by trigonometry identity \begin{array}{l} \cos (90-\beta)=\sin \beta \\ \therefore V_x=V_{\sin \beta} \end{array}
