What is the concentration (in \(\mathrm{mol} \cdot \mathrm{dm}^3\) ) of a solution containing \(0.38 \mathrm{~g}\) of potassium hydroxide \(100 \mathrm{~cm}^3\) of solution? (\mathrm{K}=39, \mathrm{H}=1, \mathrm{O}=16)\)
A. 0.028 B. 0.04 C. 0.05 D. 0.07
Correct Answer: D
Explanation
Molar mass of potassium hydroxide, \(\mathrm{KOH}=(39+16+1) \mathrm{gmol}^{-1}\) \(=56 \mathrm{gmol}^{-1}\) mole of \(\mathrm{KOH}=0.38 \mathrm{~g} / 56 \mathrm{gmol}^{-1}\) \(=0.0067857 \mathrm{~mol}\) volume of solution \(=100 \mathrm{~cm}^3\) \(=\left(\frac{100}{1000}\right) \mathrm{dm}^3=0.1 \mathrm{dm}^3\) concentration \(\left(\right.\) in mold \(\left.\mathrm{dm}^{-3}\right)=\frac{\text { mole }}{\text { volume }\left(\mathrm{dm}^3\right)}\) \(=\frac{0.0067875 \mathrm{~mol}}{0.1 \mathrm{dm}^3}\) \(=0.067857 \mathrm{moldm}^{-3}\) \(=0.07 \mathrm{moldm}^{-3}\)