To find the variance of the numbers \(k, k+1, k+\) 2 \(\operatorname{mean} \bar{x}=\frac{\sum F x}{n}=\frac{(k)+(k+1)+(k+2)}{3}=\frac{3 k+3}{3}\) \(\frac{3(k+1)}{3}=k+1\)
variance \(S^2=\frac{\Sigma(x-x)^2}{n}\)
\(S^2=\frac{[k-(k+1)]^2+[k+1-(k+1)]^2+[k+1-(k+2)]^2}{3}\)
this gives \(\Rightarrow \frac{1+0+1}{3}=\frac{2}{3}\)
\(\therefore \mathrm{S}^2=\frac{2}{3}\)