How many moles of zine would be deposited by passing \(3 \mathrm{~F}\) of electricity through a solution of \(\mathrm{ZnSO}_4\) ? (If \(=96500 \mathrm{C}\) )
A. \(1.5\) moles B. \(2.3\) moles C. \(3.4\) moles D. \(0.15\) moles
Correct Answer: A
Explanation
\(\mathrm{Zn}^{2+}+2 \mathrm{e}^{-} \rightarrow \mathrm{Zn}\) 1 mole of \(\mathrm{Zn}\) requires \(2 \mathrm{~F}\) of electricity. Thus, \(3 \mathrm{~F}\) will produce \(\left(\frac{1}{2} \times 3\right)\) mole \(=1.5\) mole of \(\mathrm{Zn}\)
