Sum of interior angle of a polygon \(=360^{\circ}\) \(\Rightarrow(\mathrm{X}+15)^{0}+(2 \mathrm{X}-45)^{0}\left(\mathrm{X}-30^{0}\right)+(\mathrm{x}+10)=360\)xpanding, \(\Rightarrow[x+2 x+x+x]+(15+10-45-30]^{0}=\) \(360^{\circ}\)
\(=5 x^{0}-50^{0}=360\),
\(x^{0}=410 / 5=82^{0}\) (values of angle)
Substituting \(x^{0}\) to get the least interior angle
\(\Rightarrow(x-15)=82^{0}+15=97\)
\(\Rightarrow(2 x-45)^{0}=\left(2(82)-45^{0}\right)^{0}=119^{0}\)
\(\Rightarrow(\mathrm{x}-30)^{0}=(82-30)^{0}=52^{0}\)
\(\Rightarrow(x+10)^{0} \Rightarrow(82+10)^{0}=52\)
\(\therefore\) The least of the interior angle \(=(x-30)^{0}\)