Two long parallel wires \(X\) and \(Y\) carry currents \(3 A\) and SA respectively, if the force experienced per unit length by \(\mathrm{X}\) is \(5 \times 10^{-5} \mathrm{~N}\), the force per unit length experienced by wire. Y wire is ____________
A. \( 5 \times 10^{-5} \) B. \( 5 \times 10^{-4} \mathrm{~N} \) C. \( 3 \times 10^{-6} \mathrm{~N} \) D. \(3 \times 10^{-5} \mathrm{~N}\)
Correct Answer:
Explanation
\(118.8 \mathrm{~cm}^{-3}\) of cupper \(10^{-3}\) or \(0.003\) in forensity \(=9 \times 10^{-3} \mathrm{kgm}^{-3}\)ensity \(=\frac{\text { mass }}{\text { Vol }}\) \(=9 \times 10^{.3} \mathrm{kgm}^{-3}=\frac{M}{118.8}=1.06292\) \(\therefore M=f I \times t\) \(\Rightarrow 1.06292=0.03 \times 10 \mathrm{xt}\) \(t=\frac{106292}{0.03}=20.0 \mathrm{mins}\)
