(a) A girl threw a stone horizontally with a velocity of 30m/s from the top of a cliff 50m high. How far from the foot of the cliff does the stone strike the ground? [Take g= 10m/s\(^2\) (b)
(b) A body A, of mass 2kg is held in equilibrium by means of two strings AP and AR. AP is inclined at 56° to the upward vertical and AR is horizontal. Find the tensions T\(_1\), and T\(_2\), in the strings [Take g= 10ms\(^2\)]
Explanation
(a) Time taken to reach the ground Using S = ut + 1/2gt\(^2\) (u= 0 for a body falling from rest) 50 = 0 x t + 1/2 x 10t\(^2\) 5t\(^2\) = 50; t\(^2\) =50/5 = 10 t = √10 =3.16 Distance when it strikes the ground This journey is independent of gravity d =vt =30 x 3.16 = 94.8m