The diagram is that of a light inextensible string of length 4.2m, whose ends are attached to two fixed points X and Y, 3m apart, and on the same horizontal level. A body of mass 800g is hung on the string at a point O, 2.4m from Y. If the system is kept in equilibrium by a horizontal force P acting on the body and the tensions are equal, calculate: (a) < XOY; (b) the magnitude of the force P; (c) the tension T in the string.
Explanation
Cos = cos = cos = = 0 cos 0 = 90 < XOY = 90
(b) Magnitude of the force p cos = cos = = cos = cos = 0.8 = cos 0.8 = 36.86 p = 2.4 x 0.8 p = 1.92N
(c) The tension T in the string T = 8 + 1.92 T = 64 + 3.59 Tv = 67.69 T = T = 8.23N