(a) Using long division

x + 2	2x${}^2$ + 7x - 15
	2x${}^3$ + 11x^2 - x -30- (2x${}^3$ + 4x${}^2$)$\overline{7^2-x-30}$- (7x${}^2$ + 14x) - 3$\overline{-15x-30}$- 15x - 30$\bar{0}$

(x + 2)(2x${}^2$ + 7x - 15)
(x + 2)(2x - 3)(x - 5)
zeros of g (x) are;
x + 2 =0, 2x - 3 = 0
x + 5 = 0, x = -2
x = $\frac{5}{2}$ and x = -5

(b) 3(2^${}^x$) + 3${}^{y-2}$ = 25 .......x1
2${}^x$ - 3${}^{y+1}$ = -19 .........x3
3(2${}^x$) + 3${}^{y-2}$ = 25
3${}^{y-2}$ + 3(3${}^{y+1}$) = 82
$\frac{3^y}{9}+\frac{3^y}{1}$ = 82
$\frac{3^y+9(3^y)}{9}$ = 82
3${}^y$ + 9(3${}^y)$) = 82 x 9
let p = 3y
p + qp = 738
$\frac{10p}{10}=\frac{738}{10}$
p = 73.8, 3${}^y$ = 73.8
log3${}^y$ = log 73.8
$\frac{ylog3}{log3}=\frac{log73.8}{\log 3}$
y = 3.9
from
2${}^x$ + 3${}^{y+1}$ = - 19
2${}^x$ + 3${}^{3.9+1}$ = - 19
2${}^x$ + 3${}^{4-9}$ = - 19
2${}^x$ - 217.7 = - 19
2${}^x$ = 198.71
log 2${}^x$ = log 198.71
$\frac{x\log 2}{log2}=\frac{log198.71}{log2}$
x = 7.6