(a) 7 - $\frac{6}{x}=3-2x$
Simplifying; $x^2+2x-2=0$
x = 1 or x = -3
Substituting for x; y = 3 - 2(1) = 3 - 2 = 1 or y = 3 - 2(-3) = 3 + 6 = 9
The coordinate of the two points are (x y) = (1, 1), (-3, 9)

(b) ($\frac{1-3}{2},\frac{1+9}{2}$) = (-1, 5)
The gradient of the point of intersection ; $\frac{9-1}{-3-1}=\frac{8}{-4}$ = -2
The gradient of the perpendicular bisector; $\frac{1}{2}$
Thus, the equation of the perpendicular bisector; y - 5 = $\frac{1}{2}$ (x + 1)
Therefore, 2y - x - 11 = 0