The probability that Kofi and Ama hit a target in a shooting competition are \(\frac{1}{6}\) and \(\frac{1}{9}\) respectively. What is the probability that only one of them hit the target?
A. \(\frac{1}{54}\) B. \(\frac{13}{54}\) C. \(\frac{20}{27}\) D. \(\frac{41}{54}\)
Correct Answer: B
Explanation
P(only one hit target) = P(Kofi not Ama) + P(Ama not Kofi) P(Kofi not Ama) = P(Kofi and Ama') = \(\frac{1}{6} \times \frac{8}{9} = \frac{8}{54}\) P(Ama not Kofi) = P(Ama and Kofi') = \(\frac{1}{9} \times \frac{5}{6} = \frac{5}{54}\) P(only one hit target) = \(\frac{8}{54} + \frac{5}{54} = \frac{13}{54}\)
